修复:将目录的子级目录权限赋予普通用户后,普通用户无法查看的问题

master
Guo XIn 1 year ago
parent 0efbcae3e3
commit 5192c15e9c
  1. 22
      shandan-system/src/main/java/com/keyware/shandan/bianmu/service/DirectoryTreeService.java

@ -53,15 +53,31 @@ public class DirectoryTreeService {
if (StringUtils.hasText(pid)) {
parentDir = directoryService.getById(pid);
}
// 获取子级节点
List<DirectoryVo> directoryList = getDirectoryList(parentDir, allChild, hasMetadata, busType);
// 审核状态
ReviewStatus status = StringUtils.hasText(reviewStatus) ? ReviewStatus.valueOf(reviewStatus) : null;
// 当前用户
SysUser user = SecurityUtil.getLoginSysUser();
// 根据权限类型获取权限范围内的数据的ID集合
Set<String> permisDis = "write".equals(permis) ? dirPermissionService.getByWritePermis(user) : dirPermissionService.getByReadPermis(user);
// 判断权限范围
List<DirectoryVo> permisDirectoryList = StreamUtil.as(directoryList).filter(dir -> {
if (status == null) {
return permisDis.contains(dir.getId());
if(dir.getReviewStatus() == status || status == null){
boolean permisAllow = permisDis.contains(dir.getId());
if(permisAllow){
return true;
}
return dir.getReviewStatus() == status && permisDis.contains(dir.getId());
// 如果权限不允许,则需要判断当前节点的所有子级节点是否有允许的目录,如果有则需要返回到前端的树组件中
Set<String> childrenIds = getDirectoryList(dir, true, false, busType).stream().map(DirectoryVo::getId).collect(Collectors.toSet());
for(String id : childrenIds){
if(permisDis.contains(id)){
return true;
}
}
return false;
}
return false;
}).toList();
DirectoryParentBuilder dpb = new DirectoryParentBuilder(directoryList, permisDirectoryList);